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55 lines
1.8 KiB
Zig
55 lines
1.8 KiB
Zig
//
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// Now that we know how to get an Io value, let's use it for
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// asynchronous execution!
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//
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// io.async() launches a function and returns a Future. The result
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// won't necessarily be available until you call .await() on it:
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//
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// var future = io.async(someFunction, .{ arg1, arg2 });
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// const result = future.await(io);
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//
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// The function *may* run immediately or on another thread -
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// your code doesn't need to care! That's the beauty of the
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// Io abstraction.
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//
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// IMPORTANT: Every Future MUST be either .await()ed or .cancel()ed.
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// Failing to do so leaks resources! A safe pattern is:
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//
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// var future = io.async(myFn, .{});
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// defer _ = future.cancel(io); // safety net
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// // ... later, if we want the result:
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// const result = future.await(io);
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// // (await after cancel is fine — it just returns the result)
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//
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// Both .await() and .cancel() block until the task finishes and
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// return the result. The difference is that .cancel() also
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// requests the task to stop at its next cancellation point.
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// Calling either one more than once is safe — subsequent calls
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// just return a copy of the result.
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//
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// Fix this program so that computeAnswer runs asynchronously
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// and its result is properly awaited.
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//
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const std = @import("std");
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const print = std.debug.print;
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pub fn main(init: std.process.Init) !void {
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const io = init.io;
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// Launch computeAnswer asynchronously.
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var future = io.async(computeAnswer, .{ 6, 7 });
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defer _ = future.cancel(io); // always clean up!
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print("Computing... ", .{});
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// Now collect the result. What method on Future gives us
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// the value, blocking until it's ready?
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const answer = future.???(io);
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print("The answer is: {}\n", .{answer});
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}
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fn computeAnswer(a: u32, b: u32) u32 {
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return a * b;
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}
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